Python 练习实例24
题目:有一分数序列:2/1,3/2,5/3,8/5,13/8,21/13...求出这个数列的前20项之和。
程序分析:请抓住分子与分母的变化规律。
程序源代码:
方法一:
实例
#!/usr/bin/python
# -*- coding: UTF-8 -*-
a = 2.0
b = 1.0
s = 0
for n in range(1,21):
s += a / b
t = a
a = a + b
b = t
print s
方法二:
实例
#!/usr/bin/python
# -*- coding: UTF-8 -*-
a = 2.0
b = 1.0
s = 0.0
for n in range(1,21):
s += a / b
b,a = a , a + b
print s
s = 0.0
for n in range(1,21):
s += a / b
b,a = a , a + b
print s
方法三:
实例
#!/usr/bin/python
# -*- coding: UTF-8 -*-
a = 2.0
b = 1.0
l = []
for n in range(1,21):
b,a = a,a + b
l.append(a / b)
print reduce(lambda x,y: x + y,l)
以上实例输出结果为:
32.6602607986
Python 100例
liwei
liwei9902@126.com
Python3 环境还可以使用以下方式实现:
#!/usr/bin/python3 a = 2 b = 1 lst = [] for i in range(20): lst.append(str(a) + '/' + str(b)) a,b = a+b, a print('{0} = {1}'.format(eval('+'.join(lst)), '+'.join(lst)))liwei
liwei9902@126.com
等一个人
252343465@qq.com
Python3 测试实例:
#!/usr/bin/env python3 # -*- coding: utf-8 -*- sum = 0 a, b = 1, 2 for i in range(1, 21): sum += b / a a, b = b, a + b print(sum)等一个人
252343465@qq.com
不知道叫啥
1147915830@qq.com
参考方法:
#!/usr/bin/python # -*- coding: UTF-8 -*- def fib(n): if n == 0 or n == 1: return n else: return int(fib(n-1) + fib(n-2)) s = 0.0 for i in range(1, 21): s += float(fib(i+2))/float(fib(i+1)) print "%s: %s/%s" % (i, fib(i+2), fib(i+1)) print s不知道叫啥
1147915830@qq.com